The JEE Primary 2019 Outcomes have been introduced by the Nationwide Testing Company (NTA). College students can examine the outcomes right here. Over 6 lakh candidates tried JEE Primary 2019 in each the windows- January and April. For these candidates, the upper percentile amongst the 2 home windows shall be thought of. Amongst these 6 lakh candidates, about half of them improved their efficiency within the April window. College students can apply for admission to the Nationwide Institutes of Expertise (NIT’s) and different Authorities Funded Technical Institutes (GFTI’s) on the premise of their JEE Primary 2019 Outcomes. The JEE Primary 2019 Outcomes will even decide their eligibility for the JEE Superior 2019.
| Variety of Check-takers in January window | 8,74,469 |
| Variety of Check-takers in April window | 8,81,096 |
| Widespread Check-takers in each home windows | 6,08,440 |
| Complete Check-takers | 11,47,125 |
| Variety of test-takers with 100 percentile | 24 |
This time, round 2.45 lakh candidates are eligible to jot down JEE Superior. The cut-offs(percentile) to jot down the JEE Superior 2019 examination are:
| CATEGORY | CUT-OFF PERCENTILE |
| Widespread Rank Listing/Common (CRL) | 89.7548849 |
| Economically Weaker Part (EWS) | 78.2174869 |
| Different Backward Class (OBC) | 74.3166557 |
| Scheduled Caste (SC) | 54.0128155 |
| Scheduled Tribe (ST) | 44.3345172 |
| Individuals with Incapacity (PwD) | 0.1137173 |
The percentile rating in JEE Primary 2019 Outcomes signifies the share of candidates who’ve scored equal to, or beneath, that specific percentile in that session. The components to calculate your rating is talked about beneath:
Percentile Rating of a Candidate = 100 X[No. of candidates who secured a raw score (or actual score) equal to, or less than, the candidate) ÷ (Total no. of candidates who appeared in that session)
In order to read about the process followed to calculate percentile, rank and normalise scores in detail, you can see the official notification here.
The next stage for students who have cleared the JEE Main 2019 is the JEE Advanced 2019. Candidates who clear the JEE Advanced are eligible to get a seat in any one of the 23 prestigious Indian Institutes of Technology (IIT’s). The registration for JEE Advanced 2019 starts on 3rd May. You can check the important dates, eligibility, format and other related information about JEE Advanced 2019 here.
Students with a JEE Main score are also eligible to participate in the JoSAA process. The Joint Seat Allocation Authority (JoSAA) has been formed by the Ministry of Human Resources Development (MHRD) to manage and regulate admissions to the participating institutes. In 2018, the following 100 institutes participated in the counselling process-
| S.No | Institutes | Number of Colleges under Institute |
| 1 | Indian Institute of Technology | 23 |
| 2 | National Institute of Technology | 31 |
| 3 | Indian Institute of Information Technology | 24 |
| 4 | Government Funded Technical Institutes | 22 |
Apart from these colleges, several state colleges also participate in this process.
At Career Launcher, we run various online and offline programs for coaching JEE Advanced candidates. Check out these programs and our results. You can give free mock tests and chapter tests along with regular updates of important exam news and notifications at our online learning platform, aspiration.ai. Write to us for any queries or feedback in the comments below. We wish you the very best for your JEE Advanced exam!